On Thu, 13 Apr 2006 12:09:32 -0700, Kelvie Wong wrote:
> try this:
>
> string = 'D c a V e r " = d w o r d : 0 0 0 0 0 6 4 0'
> import re
> re.sub("\s", "", string)
Why would you want to call in the heavy sledgehammer of regular
expressions for cracking this peanut?
old_s = 'D c a V e r " = d w o r d : 0 0 0 0 0 6 4 0'
new_s = old_s.replace(" ", "")
And if you want to remove all whitespace:
new_s = "".join(old_s.split())
--
Steven.
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