Ben Cartwright wrote: > Yes, and no extra for loops are needed! You can define groups inside > the lookahead assertion: > > >>> import re > >>> re.findall(r'(?=(aba))', 'abababababababab') > ['aba', 'aba', 'aba', 'aba', 'aba', 'aba', 'aba']
Wow, that was like magic! :) -- http://mail.python.org/mailman/listinfo/python-list
