Hey all, in perl I was able to use the same regular expression multiple times changing one part of it via a previously defined array and put the results into a new array
IN PERL: my @targets = ('OVERALL RATING', 'CLOTHING', ' ITEMS', 'ACCESSORIES', 'SHOES', 'FINE JEWELRY'); my @JA13 = map { $file2 =~/$_.*?(?:(\d{1,3}\.\d)\s+){3}/s; } @targets; So, in python instead of match2 = re.search('OVEWRALL RATING.*?(?:(\d{1,3}\.\d)\s+){3} ', file2);m01 = match2.group(1) ;print m01 match2 = re.search('CLOTHING.*?(?:(\d{1,3}\.\d)\s+){3} ', file2); m02 = match2.group(1) ;print m02 match2 = re.search('ITEMS.*?(?:(\d{1,3}\.\d)\s+){3} ', file2); m03 = match2.group(1) ;print m03 match2 = re.search('ACCESSORIES.*?(?:(\d{1,3}\.\d)\s+){3} ', file2); m04 = match2.group(1) ;print m04 match2 = re.search('SHOES.*?(?:(\d{1,3}\.\d)\s+){3} ', file2); m05 = match2.group(1) ;print m05 match2 = re.search('FINE JEWELRY.*?(?:(\d{1,3}\.\d)\s+){3} ', file2); m06 = match2.group(1) ;print m06 I would have something similar to perl above: targets = ['OVERALL RATING', 'CLOTHING', ITEMS', 'ACCESSORIES', 'SHOES', 'FINE JEWELRY'] PROPOSED CODE: match2 = re.search(targets[i].*?(?:(\d{1,3}\.\d)\s+){3} ', file2);m[i] = match2.group(1) Lance -- http://mail.python.org/mailman/listinfo/python-list