In <[EMAIL PROTECTED]>, luca72 wrote:
> Hello again i have solve doing this:
>
> from Crypto.Cipher import AES
> stri=(chr(int('9b',16))+chr(int('d3',16))+chr(int('2d',16))+chr(int('24',16))+chr(int('af',16))+chr(int('c9',16))+chr(int('e9',16))+chr(int('d7',16))+chr(int('46',16))+chr(int('69',16))+chr(int('71',16))+chr(int('32',16))+chr(int('45',16))+chr(int('5f',16))+chr(int('27',16))+chr(int('0b',16)))
> luca = str(stri)
> crypt = AES.new(luca, AES.MODE_ECB)
> testo=(chr(int('ea',16))+chr(int('52',16))+chr(int('3a',16))+chr(int('66',16))+chr(int('4d',16))+chr(int('ab',16))+chr(int('aa',16))+chr(int('44',16))+chr(int('76',16))+chr(int('d3',16))+chr(int('12',16))+chr(int('26',16))+chr(int('a1',16))+chr(int('e3',16))+chr(int('ba',16))+chr(int('b0',16)))
> testo = str(testo)
> c = crypt.encrypt(testo)
>
> I don't know if this is the best way , but anyway it work
In [26]:import binascii
In [27]:binascii.unhexlify('ea523a664dabaa4476d31226a1e3bab0')
Out[27]:'\xeaR:fM\xab\xaaDv\xd3\x12&\xa1\xe3\xba\xb0'
Ciao,
Marc 'BlackJack' Rintsch
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