Diez B. Roggisch wrote: > print [i for i, _ in enumerate((None for v in zip(a, b) where v == > (1,1)))] > > should give you the list of indices.
I musunderstood your question. Use print [i for i, _ in enumerate((None for x, y in zip(a, b) where x == y))] instead. Diez -- http://mail.python.org/mailman/listinfo/python-list
