Jason wrote:
> I believe what you are trying to do is something like the following.
>
> [code]
> def isIntLike(x):
> try: int(x)
> except: return False
*Never* ever use a bare except clause. *Always* specify wich exceptions
you are expecting. (NB : here, TypeError and ValueError).
(NB : of course, like for all and any do's-and-don't rules, there are
actually a very few cases where using a bare except may be ok.)
> else: return True
>
> something = raw_input("Enter something and I will tell you the type: ")
>
> if isIntLike(something): print "I am an int"
Nope. At this stage, 'something' is *not* an int - it's a string that
can be turned into an int.
> elif isinstance(something, type('')): print "I am a string"
You don't need the "type('')" stuff - use isinstance(something,
basestring) instead.
> else: print "I am an impostor!"
> [/code]
(snip)
--
bruno desthuilliers
python -c "print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
p in '[EMAIL PROTECTED]'.split('@')])"
--
http://mail.python.org/mailman/listinfo/python-list
