Fredrik Lundh wrote:
> the XML-RPC protocol uses HTTP POST, so if you can handle XML-RPC, you
> should be able to handle any POST request. what server are you using ?
I need some clarification of your suggestion. Instead of sending URLs,
I could read the file as a string, create a Binary object, and send
that via XML-RPC. The parameters will be sent to the server via HTTP
POST. However, the file will be encoded as a base64 string and
included in the body of the XML-RPC message, so it will have to be
parsed by the server. In my experience with SOAP, I have found this to
be extremely inefficient.
Are you suggesting sending the file separately thought a 2nd HTTP POST
with no XML-RPC message body? I guess the POST request would look
something like:
POST /path/file HTTP/1.0
From: ...
User-Agent: ...
Content-Type: /application/binary
Content-Length: <file size>
<file contents>
I'm not sure how to add a 2nd request like this. How would I alter a
simple call like that below to inlcude the 2nd post? Do I need to use
httplib and the request() method of HTTPConnection? Or can I make
POSTs through a ServerProxy object?
import xmlrpclib
server = xmlrpclib.ServerProxy("http://myserver";)
result = server.my_function(file, params)
Jeremy
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