> server = SimpleXMLRPCServer.SimpleXMLRPCServer(("xxx.xxx.xxx.xxx",
> 22999))

Could it be that xxx.xxx.xxx.xxx stands for '127.0.0.1'? If so... rename  
it to 'localhost'. If you bind a port to 127.0.0.1 it will be found only  
on the same machine.
Greetings,
Marco

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