The following function declaration incorrectly gives a C0322 ("Operator not
preceded by a space") error.
@f(a=2,
b=3)
def g1(x):
print x
The following three elements need to all be present in order to generate
this error:
-- using a function call expression as a function decorator
-- the expression must be split over multiple lines
-- the function is called using a keyword argument
A more full example is below.
James.
--
$ cat /tmp/test.py
def f(a, b):
print a, b
# Generates C0322.
@f(a=2,
b=3)
def g1(x):
print x
# The following are all fine.
@f(a=2,
b=3)
def g2():
pass
@f(a=2, b=3)
def g3(x):
print x
f(a=2,
b=3)
$ pylint /tmp/test.py
************* Module test
C0322: 6:g1: Operator not preceded by a space
b=3)
^
def g1(x):
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