Tim, thanks for your patience :). I think I'm still miscommunicating to you what I need to do. Let's throw the whole shortcut idea out the window and start from scratch.
My code generates a file, I want to open the directory (which is known) containing that file and select it. Since I can open the directory with os.startfile(), do I still need to get the hwnd of the explorer window and get the listctrl etc., or is there a simpler way to select a file? -Kyle Rickey -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Tim Roberts Sent: Thursday, April 03, 2008 12:17 PM To: Python-Win32 List Subject: Re: [python-win32] Find Target Rickey, Kyle W wrote: > Tim, let me rephrase. I'm not trying to display the shortcut dialog, > only reproduce the behavior that happens when you click 'Find Target'. > For instance, I've generated a file and I want show the user that file > in explorer. > "Find Target" just follows a shortcut and opens the directory containing that shortcut. The shell library has an API for fetching the target path from a shortcut file. You could just pull the path from the shortcut, and startup a new Explorer in that directory. -- Tim Roberts, [EMAIL PROTECTED] Providenza & Boekelheide, Inc. _______________________________________________ python-win32 mailing list python-win32@python.org http://mail.python.org/mailman/listinfo/python-win32 _______________________________________________ python-win32 mailing list python-win32@python.org http://mail.python.org/mailman/listinfo/python-win32
