le dahut wrote:
Hello,
When launching an app that opens a socket, windows Vista complains
that I have to accept it before it is launched and then that the
firewall accepts the opening of the port.
Is there a way to register my app to be launched by users without UAC
warning ?
Is there a way to open the port on the firewall inside the program or
its installer ?
You can tweak the firewall settings, but you have to be UAC to do so,
because you have to write to the HKEY_LOCAL_MACHINE registry hive. If
you have a setup application that has "setup" in the file name, this
should work. BTW, this may be the longest registry path you will ever
encounter:
HKEY_LOCAL_MACHINE\
System\
CurrentControlSet\
Services\
SharedAccess\
Parameters\
FirewallPolicy\
DomainProfile\
AuthorizedApplications\
List\
Within that key, create a REG_SZ value whose name is the path to your
application, whose value is a 4-part string separated by colons:
<path-to-app>:*:Enabled:<friendly name>
Put the same thing into
...
StandardProfile\
AuthorizedApplications\
List\
--
Tim Roberts, [EMAIL PROTECTED]
Providenza & Boekelheide, Inc.
_______________________________________________
python-win32 mailing list
python-win32@python.org
http://mail.python.org/mailman/listinfo/python-win32
