On 10/04/2012 3:40 AM, jeffwe...@earthlink.net wrote:
My apologies to the list about my earlier question that was in html. My webmail
is supposed to default to plain text but clearly did not.
I am trying to write a Python server that will be used by a C++ client. It has
taken me quite a while longer than I expected. I have been through the archives
and that helped me get to where I am. Many thanks to all those who support
these packages.
I am using Python 2.5.1 as it is required by some vendor equipment that I must
use.
One of the reasons it took me a while to get this going was that I was trying
to test it in Python. Once I switched to testing it in VBA then I made much
faster progress.
For demonstration purposes I used the Pippo test in the 'win32com\test'
directory. I modified the testpippo.py by adding some code at the start of the
testLeaks method. I added the 4 lines:
in1 = 15
inout1 = 99
hr= self.object.Method3( in1, inout1)
print hr, "retval = %d inout1 = %d"%(hr[0], hr[1])
>
>
> The printed line was "(0, -31) retval = 0 inout1 = -31".
>
what is Method3 here? The pippo tests don't have such a method.
But note that in Python, you generally don't see the "hresult" - so it
would be more accurate to have it read something like:
results = self.object.Method3( in1, inout1)
as Python doesn't have a concept of "byref" args, the "results" object
is a tuple with the return value of the function, if any, plus any
"byref" args created. In the example above, I'm guessing the function
has returned 0 and one byref arg was presented, with the new value being
-31.
In the VB example below, VB does have byrefs, so the out args end up in
the same argument they were passed in.
I can't explain why VB for -41 for the result when Python got zero
though, but I also can't find the "method3" to help explain it.
Mark
I get "retval = -41 inout1= -31" if I execute the VBA code:
Sub TestPippo()
Dim obj As Pippo
Dim in1 As Long
Dim inout1 As Long
Set obj = CreateObject("Python.Test.Pippo")
in1 = 1
inout1 = 2
retval = obj.Method3(in1, inout1)
MsgBox ("retval = " & retval & " inout1 = " & inout1)
End Sub
Is there a way to call the same Python Server Method, Method3, so that both
Python and VBA receive the same return data?
Regards,
j
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