I am trying to write a deformer script for maya, using the maya API which
deforms any mesh into a sphere by translating it's vertices.
What i already have is a deformer which translates every vertex of mesh in
the direction of it's normal with the amount specified. This is done using
the below equation.
point += normals[itGeo.index()] * bulgeAmount * w * env;
Where, point is the vertex on the mesh. normals[itGeo.index()] is a vector
array which represents the normals of each vertex. w and env are to control
the weights of the deformation and the envelope.
What this code basically does is, it translates the vertex in the direction
of the normal with the amount specified. While this works for a sphere,
because a sphere's vertex normals would point at the center. It would not
work for other meshes as the normals would not point at the center of the
mesh.
float bulgeAmount = data.inputValue(aBulgeAmount).asFloat();
float env = data.inputValue(envelope).asFloat();
MPoint point;
float w;
for (; !itGeo.isDone(); itGeo.next())
{
w = weightValue(data, geomIndex, itGeo.index());
point = itGeo.position();
point += normals[itGeo.index()] * bulgeAmount * w * env;
itGeo.setPosition(point);
}
I initially thought changing the direction of translation would solve the
problem. As in, if we can find the vector in the direction from the center
of the mesh to each vertex and translate it along that direction for an
amount specified would solve it. Like so :
point += (Center - point) * bulgeAmount * w * env;
Where, Center is the center of the mesh. But this does not give the desired
result. I also would want the deformer to be setup in such a way that the
user can input radius "r" value and can also change the amount attribute
from 0 to 1 to deform the mesh from it's original state to a spherical one.
So that he can choose a value in between if her desires and the mesh would
be something between a sphere and it's original shape.
This is my very first post in this group. I apologize if the format does
not follow the community expectations. Any help on this will be greatly
appreciated.
Thank You.
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