That's nice, thanks!
-----
Yury Katkov
On Mon, Aug 6, 2012 at 8:19 PM, Max Klein <isa...@gmail.com> wrote:
>>
>> From: Yury Katkov <katkov.ju...@gmail.com>
>> To: MediaWiki announcements and site admin list
>> <mediawik...@lists.wikimedia.org>, pywikipedia-l@lists.wikimedia.org
>> Cc:
>> Date: Mon, 6 Aug 2012 16:05:03 +0400
>> Subject: [Pywikipedia-l] Automatic generation of templates descriptions
>> Hello! Is there a bot or extension that can generate stubs of template
>> descriptions by template wikitext? It should be pretty simple: the bot will
>> just grab all template parameters {{{PARAMETER}}} and lists those
>> parameters.
>>
>> If no such extensions exists could anybody tell how to programaticaly get
>> the parameters of a given template?
>
>
> Hi Yury,
> I actually just solved this problem myself. There is indeed a method of
> pywikipediabot that does this - it's called templatesWithParams()
>
> Here is a code example where I am looking to get see what the "VIAF"
> parameter is of the {{Authority Control}} template:
>
> def determineAuthorityControlTemplate(nameOfPage):
> """returns 'noACtemplate' if no Authority Control Template,
> 'templateNoVIAF' if AC template but no VIAF number,
> and returns the viaf number if it exists"""
> namepage = Page(enwp,nameOfPage)
> templates = namepage.templatesWithParams() #here we load the templates
> into a list
> for template in templates: # go through the templates
> if template[0] == 'Authority control': # are we looking at the right
> template?
> for param in template[1]: #go through the paramaters of the
> template
> if param[:4] == 'VIAF': #are we looking at the right
> parameter?
> return param[5:]
> return 'templateNoVIAF'
> return 'noACtemplate'
>
> Best,
> Max
>>
>>
>>
>>
>> Sincerely yours,
>> -----
>> Yury Katkov
>>
>>
>>
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>
>
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