Hi all, I'm running QEMU 0.9.0 under RHEL 4 (I SSH'ed to the Linux machine).
If I issue the following command, it boots up but it won't show the command line prompt. qemu-system-sparc -L ..*/qemu/pc-bios/* -kernel ../qemu/sparc-test/vmlinux- 2.6.11+tcx -initrd ../qemu/sparc-test/linux.img -append "root=/dev/ram console=ttyS0 video=tcxfb:off" -nographic The last line showed is "Freeing unused kernel memory: 156k freed". I had to kill the qemu session from another terminal. But I did see the following lines during its boot-up: Console: ttyS0 (SunZilog zs0) ttyS0 at MMIO 0x0 (irq = 44) is a SunZilog ttyS1 at MMIO 0x0 (irq = 44) is a SunZilog However, if I remove "console=ttyS0" from the qemu command line, it boots up and I can get the command line prompt as follows (I got the same "Console: ttyS0 (SunZilog zs0)" message (listed above)): ... Freeing unused kernel memory: 156k freed sh: can't access tty; job control turned off # ls /dev console ttyS0 ttyS1 ttyS2 ttyS3 # Can someone tell me the reason? Also how do I get rid of the message "sh: can't access tty; job control turned off" (and what it means?) ? Thanks in advance! Wesley P.S. Please reply me directly as I am not in the alias.
