Am 11.08.2010 11:06, schrieb C K Kashyap:
Let me see if I understand this right -
qemu loads the a.out and begins to interpret the x86 instructions in
the a.out and when a system call happens, it makes the call the host
system .... is that right?
Right. That's the way how linux user mode emulation (for example
qemu-i386) works.
See linux-user/syscall.c if you want to see more details.
bsd-user and darwin-user are also supported (more or less), but darwin-user
only supports translation of darwin/powerpc to darwin/x86 syscalls.
It won't help you to run a linux a.out on your mac.
On Wed, Aug 11, 2010 at 2:12 PM, Stefan Weil <w...@mail.berlios.de
<mailto:w...@mail.berlios.de>> wrote:
Am 11.08.2010 10:31, schrieb C K Kashyap:
Hi,
I've built qemu on my mac osx using this config -
./configure --prefix=/Users/ckk/local/
--target-list="i386-softmmu x86_64-softmmu" --enable-linux-user
Now, I have a simple a.out built on linux - how can I run it
using qemu on my mac box?
--
Regards,
Kashyap
Hi Kashyap,
you cannot run it in user mode emulation unless you replace Mac OS
by Linux
on your mac box. Linux user emulations requires a Linux host.
If you have a Linux host, you would need
--target-list=i386-linux-user.
You can run your a.out if you run system emulation (e.g.
i386-softmmu/qemu)
and install Linux there, of course.
Regards,
Stefan
--
Regards,
Kashyap
