When using xen_enabled() we're currently only checking if xen is enabled
at all during the build. But what if you want to build multiple targets
out of which only one can potentially run xen code?

That means that for generic code we'll still have to fall back to the
variable and potentially slow the code down, but it's not as important as
that is mostly xen device emulation which is not touched for non-xen targets.

The target specific code however can with this patch see that it's unable to
ever execute xen code. We can thus always return 0 on xen_enabled(), giving
gcc enough hints to evict the mapcache code from the target memory management
code.

Signed-off-by: Alexander Graf <ag...@suse.de>
Acked-by: Anthony PERARD <anthony.per...@citrix.com>
---
 configure |    5 +++++
 hw/xen.h  |    2 +-
 2 files changed, 6 insertions(+), 1 deletions(-)

diff --git a/configure b/configure
index cd399dc..bc3495c 100755
--- a/configure
+++ b/configure
@@ -3290,7 +3290,12 @@ case "$target_arch2" in
     if test "$xen" = "yes" -a "$target_softmmu" = "yes" ; then
       target_phys_bits=64
       echo "CONFIG_XEN=y" >> $config_target_mak
+    else
+      echo "CONFIG_NO_XEN=y" >> $config_target_mak
     fi
+    ;;
+  *)
+    echo "CONFIG_NO_XEN=y" >> $config_target_mak
 esac
 case "$target_arch2" in
   i386|x86_64|ppcemb|ppc|ppc64|s390x)
diff --git a/hw/xen.h b/hw/xen.h
index 43b95d6..2162111 100644
--- a/hw/xen.h
+++ b/hw/xen.h
@@ -24,7 +24,7 @@ extern int xen_allowed;
 
 static inline int xen_enabled(void)
 {
-#ifdef CONFIG_XEN_BACKEND
+#if defined(CONFIG_XEN_BACKEND) && !defined(CONFIG_NO_XEN)
     return xen_allowed;
 #else
     return 0;
-- 
1.6.0.2


Reply via email to