Please stop asking questions using a bug tracking system, this is rude. No it is not a bug, it appears you can't do simple arithmetics, -- the pointer is increased by 16 bytes not 2.
** Changed in: qemu Status: New => Invalid -- You received this bug notification because you are a member of qemu- devel-ml, which is subscribed to QEMU. https://bugs.launchpad.net/bugs/1894029 Title: qemu-i386 malloc error Status in QEMU: Invalid Bug description: Hi!I use qemu-i386-static on 64 bit machines.And memory request succeeded, but the pointer is wrong. This is my test program: #include <stdint.h> #include <stdio.h> #include <stdlib.h> #include <unistd.h> int main(int argc, char **argv) { void *pa=0,*pb=0,*pc=0,*pd=0; pa = malloc(sizeof(uint32_t)); pb = malloc(sizeof(uint32_t)); pc = malloc(4); pd = malloc(4); printf("pa: 0x%x\n",pa); printf("pb: 0x%x\n",pb); printf("pc: 0x%x\n",pc); printf("pd: 0x%x\n",pd); printf("uint32_t:%d\n",sizeof(uint32_t)); free(pa); free(pb); free(pc); free(pd); return 0; } And it is wrong: pa: 0x400051a0 pb: 0x400051b0 pc: 0x400051c0 pd: 0x400051d0 uint32_t:4 Why did I apply for 4 bytes of space, but the pointer only increased by 2 bytes?? Is it a BUG?? To manage notifications about this bug go to: https://bugs.launchpad.net/qemu/+bug/1894029/+subscriptions