The number of runs is equal to the number of 0-1 and 1-0 transitions, plus one. Currently, it's counting the number of times these transitions do _not_ happen, plus one.
Source: https://nvlpubs.nist.gov/nistpubs/Legacy/SP/nistspecialpublication800-22r1a.pdf section 2.3.4 point (3). Signed-off-by: Havard Skinnemoen <hskinnem...@google.com> --- tests/qtest/npcm7xx_rng-test.c | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/tests/qtest/npcm7xx_rng-test.c b/tests/qtest/npcm7xx_rng-test.c index da6e639bf6..57787c5ffc 100644 --- a/tests/qtest/npcm7xx_rng-test.c +++ b/tests/qtest/npcm7xx_rng-test.c @@ -126,7 +126,7 @@ static double calc_runs_p(const unsigned long *buf, unsigned int nr_bits) pi = (double)nr_ones / nr_bits; for (k = 0; k < nr_bits - 1; k++) { - vn_obs += !(test_bit(k, buf) ^ test_bit(k + 1, buf)); + vn_obs += (test_bit(k, buf) ^ test_bit(k + 1, buf)); } vn_obs += 1; -- 2.29.1.341.ge80a0c044ae-goog
