On 14/1/22 16:37, Peter Maydell wrote:
The linux-user queue_signal() function always returns 1, and none of
its callers check the return value. Give it a void return type
instead.
The return value is a leftover from the old pre-2016 linux-user
signal handling code, which really did have a queue of signals and so
might return a failure indication if too many signals were queued at
once. The current design avoids having to ever have more than one
signal queued via queue_signal() at once, so it can never fail.
Signed-off-by: Peter Maydell <peter.mayd...@linaro.org>
---
linux-user/signal-common.h | 4 ++--
linux-user/signal.c | 5 ++---
2 files changed, 4 insertions(+), 5 deletions(-)
Reviewed-by: Philippe Mathieu-Daudé <f4...@amsat.org>
