On 4/22/22 04:53, Pavel Dovgalyuk wrote:
+void icount_notify_exit(void)
+{
+    if (icount_enabled() && first_cpu) {
+        cpu_exit(first_cpu);
+        qemu_clock_notify(QEMU_CLOCK_VIRTUAL);
+    }
+}

Why first_cpu?  Did you really want to continue to the end of the round-robin?
Otherwise I'd expect qemu_cpu_kick(current_cpu), or something.


r~

Reply via email to