Since MULTU opcodes don't record the most significant bits
of the infinite result, sign-extending the sources make no
difference in the result.
Once we remove the sign extension of source registers, MULT
and MULTU are identical (as are DMULT and DMULTU).
Suggested-by: Richard Henderson <richard.hender...@linaro.org>
Signed-off-by: Philippe Mathieu-Daudé <phi...@linaro.org>
---
target/mips/tcg/translate.c | 2 --
1 file changed, 2 deletions(-)
diff --git a/target/mips/tcg/translate.c b/target/mips/tcg/translate.c
index 9bb40f1849..e0a76b9432 100644
--- a/target/mips/tcg/translate.c
+++ b/target/mips/tcg/translate.c
@@ -3625,8 +3625,6 @@ static void gen_loongson_integer(DisasContext *ctx,
uint32_t opc,
break;
case OPC_MULTU_G_2E:
case OPC_MULTU_G_2F:
- tcg_gen_ext32u_tl(t0, t0);
- tcg_gen_ext32u_tl(t1, t1);
tcg_gen_mul_tl(cpu_gpr[rd], t0, t1);
tcg_gen_ext32s_tl(cpu_gpr[rd], cpu_gpr[rd]);
break;
--
2.41.0
