Oops, my mistake. I have ##lrm=output raster in the header, but lpf = ... Is the only line in my code.
I don't get the error message after changing lrm to lpf in the header. I do get another error message, but I think I broke my processing by trying to force an update. I'll test it tomorrow. Sorry about the confusion! Eric On Mar 22, 2014 5:06 PM, "Eric Goddard" <egoddard1...@gmail.com> wrote: > Ah, I didn't know a file could he specified without a path. Thanks for the > clarification! > On Mar 22, 2014 4:37 PM, "Victor Olaya" <vola...@gmail.com> wrote: > >> > If I run the same line in the python console, it works correctly: >> >>>> radius = 4 >> >>>> lpf = processing.runalg("saga:simplefilter", "SR_50M_alaska_nad", 0, >> 0, radius, None) >> >>>> processing.load(lpf['RESULT']) >> > >> > Results in the map being loaded. >> >> Not sure why this is happening. I will try to reproduce the error and >> see if it can be fixed >> Thanks for the report >> >> > >> > Also, if I change the output folder in the processing settings to a >> > different location (in this case, tmp/processing in my home folder) >> > and run another algorithm in the python console, the RESULT key still >> > points to /tmp/processing/... >> >> This is not a bug. If you do not enter a filename, the output will >> always go to a temporary file. The output folder that yu can set in >> the settings is the folder to be used when you enter a filename >> without a path (like "myfile.shp", but not "/home/myuser/myfile.shp"), >> not the folder to use for temporary files. >> >> Thanks again! >> >
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