Hi,
The result of you operation will give you a raster with 0 (does not correspond
) and 1 (does correspond). Then you need to multiply result that by 5.
You can do it in one shot such as (raster < 2)*5. If you do (raster
<2)*raster, the results (1) will be multiplied by the original values of the
raster. All other value will be multiplied by 0.
Nicolas Cadieux M.Sc.
Les Entreprises Archéotec inc. 
8548, rue Saint-Denis Montréal H2P 2H2
Téléphone: 514.381.5112  Fax: 514.381.4995
www.archeotec.ca
Le 2015-04-08 18:30, "Giacomo Fontanelli-2 [via OSGeo.org] "
<ml-node+s1560n5200510...@n6.nabble.com> a écrit :
Dear forum I use QGIS 2.8.1. I have a raster map, Float32, pixel values
range from -0.7 to 1. I Would like to make a map with pixel having only two
values: pixels with values <= 0 should be 0 pixels with values > 0
should be 5. the sintax ( "3_NDFI@1" <= 0 ) =0 AND (
"3_NDFI@1" > 0 ) =5 doesn't work because it produces a
map with only 0 values. In order to reach my goal I must do (
"3_NDFI@1" <= 0 ) =0 AND ( "3_NDFI@1" >
0 ) =1 then multiply result by 5. What's the problem? Is it possible
to fulfil the purpose with only one raster operation? Thank you very much
_______________________________________________
Qgis-user mailing list
[hidden email]
http://lists.osgeo.org/mailman/listinfo/qgis-user
If you reply to this email, your message will be added to the
discussion below:
http://osgeo-org.1560.x6.nabble.com/making-mistakes-with-raster-calculator-tp5200510.html
To start a new topic under Quantum GIS - User, email
ml-node+s1560n4125267h38@n6.nabble.com
To unsubscribe from Quantum GIS - User, click here .
NAML
--
View this message in context:
http://osgeo-org.1560.x6.nabble.com/making-mistakes-with-raster-calculator-tp5200510p5200514.html
Sent from the Quantum GIS - User mailing list archive at Nabble.com._______________________________________________
Qgis-user mailing list
Qgis-user@lists.osgeo.org
http://lists.osgeo.org/mailman/listinfo/qgis-user
