Hi Hanlie

Yes, probably that part of documentation have to be updated.
OpenGeo plugin, since months has been substitute with Geoserver explorer plugin.
You should install it using common Plugin Manager.

https://plugins.qgis.org/plugins/geoserverexplorer/

Check if you replicate the error with the new plugin version.

From OpenGeo plugin, the Postgis and QGIS Project parts has been
removed to use the standard QGIS functions (DB Manager and Browser).

regards
Luigi Pirelli

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On 7 March 2016 at 10:53, Hanlie Pretorius <hanlie.pretor...@gmail.com> wrote:
> Hi,
>
> I'm busy running through the tutorial at
> http://suite.opengeo.org/docs/latest/qgis/explorer/tutorial/index.html
> but at step 10, after I click OK to publish the 'dem' layer (a
> raster), I get the following error:
>
> -----
> 'QgsRasterLayer' object has no attribute 'geometryType'
> Traceback (most recent call last):
>   File 
> "C:/PROGRA~2/BOUNDL~1/QGIS/qgis/apps/qgis/./python/plugins\opengeo\gui\explorer.py",
> line 111, in run
>     command(*params)
>   File 
> "C:/PROGRA~2/BOUNDL~1/QGIS/qgis/apps/qgis/./python/plugins\opengeo\qgis\catalog.py",
> line 475, in publishLayer
>     sld = self.publishStyle(layer, overwrite, name)
>   File 
> "C:/PROGRA~2/BOUNDL~1/QGIS/qgis/apps/qgis/./python/plugins\opengeo\qgis\catalog.py",
> line 148, in publishStyle
>     sld, icons = getGsCompatibleSld(layer)
>   File 
> "C:/PROGRA~2/BOUNDL~1/QGIS/qgis/apps/qgis/./python/plugins\opengeo\qgis\sldadapter.py",
> line 199, in getGsCompatibleSld
>     return adaptQgsToGs(sld, layer)
>   File 
> "C:/PROGRA~2/BOUNDL~1/QGIS/qgis/apps/qgis/./python/plugins\opengeo\qgis\sldadapter.py",
> line 61, in adaptQgsToGs
>     if layer.geometryType() == QGis.Point:
> AttributeError: 'QgsRasterLayer' object has no attribute 'geometryType'
> -----
>
> When I Googled it, I just get one unanswered question in StackExchange:
> http://gis.stackexchange.com/questions/183100/qgis-opengeo-explorer-plugin-fails-when-publishing-with-qgsrasterlayer-object
>
> Does anyone know what is going on?
>
> Thanks
> Hanlie
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