Hi,I can figure this on out!!! I want to use the layer name of the input layer (a raster) as value for the field calculator.
layer_property(@Inputraster , 'name') does not work. Any suggestions? Thanks -- Nicolas Cadieux https://gitlab.com/njacadieux _______________________________________________ Qgis-user mailing list Qgis-user@lists.osgeo.org List info: https://lists.osgeo.org/mailman/listinfo/qgis-user Unsubscribe: https://lists.osgeo.org/mailman/listinfo/qgis-user
