Hi Dietrich,
i'm not sure this is this the correct way to do this, but you can try
smth. like this:
for( var i=0; i<listitems.length; i++)
{
listitems[i].addState("color"+[i]);
}
so all listitems have different States(color1, color2, color3...)
and then:
theme.registerAppearance("colored-list-item", {
setup : function() {
{
this.color1 = new qx.renderer.color.ColorObject("#FFFFF1");
this.color2 = new qx.renderer.color.ColorObject("FFFFF2");
.
.
},
and:
state : function(vTheme, vStates)
{
return {
backgroundColor : vStates.color1 ? this.color1 : (vStates.color2 ? :
this.color2..........
};
}
this is nothing i have tested - just an idea. I'm sure there should be a
better way to do this.
Cheers,
alex.d
> Hello List,
>
> I'd like to create an appearance where I'm able to set the state
> appearance depending on a widgets property. In the example above I've
> defined a property backgroundColorUnselected which is set for each
> instance individually.
>
> So if the state changes to unselected the value of this property should
> be passed back by the state part of the appearance. Before the last
> changes to the appearance theme there was a parameter vWidget which
> contained the instance of the widget the appearance was associated with.
> How can this be done?
>
> Here is an appearance skeleton which should help to understand my needs:
>
> theme.registerAppearance("colored-list-item", {
> setup : function() {
> {
> this.bgcolor_selected = new
> qx.renderer.color.ColorObject("highlight");
> this.color_selected = new
> qx.renderer.color.ColorObject("highlighttext");
> },
>
> initial : function(vTheme)
> {
> /* initial code here */
> },
>
> state : function(vTheme, vStates)
> {
> return {
> backgroundColor : vStates.selected ? this.bgcolor_selected :
> widgetInstance.getBackgroundColorUnselected(),
> color : vStates.selected ? this.color_selected : null
> };
> }
> });
>
> Thank you for your help.
>
> Best regards...
>
>
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