smartjo wrote:
> Hi skar,
> Thank s for ur suggestion. I tested that way and here is
> the code.
>
> var doc = this.getRoot();
> var t1 = new qx.ui.form.TextField();
> t1.addListener('appear',function(){alert('creating
> t1');},this,false);
>
> var t2 = new qx.ui.form.TextField();
> t2.addListener('appear',function(){alert('creating
> t2');},this,false);
>
> var t3 = new qx.ui.form.TextField();
> t3.addListener('appear',function(){alert('creating
> t3');},this,false);
>
> doc.add(t1,{left:10,top:30})
> alert(1);
> doc.add(t2,{left:100,top:30})
> alert('2');
> doc.add(t3,{left:200,top:30})
> alert('3');
>
> And the result was like this. t1 appeared first and its event handler was
> executed. but after that the event handlers for t2 nd t3 was executed after
> alert(3) was executed. their event handlers were not executed immediately
> they were added. I hope you understand. Any solution for this?
>
If you want some code to run when a textfield is being shown, put that
code in the "appear" listener's function, or if the code is in a
function, call that function from the listener.
If this doesn't solve your problem, I need more info on what you want to
achieve.
cheers,
skar.
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