I have created a contribution widget with its own theming:
Appearance.js
-------------------
qx.Theme.define("q.theme.Appearance",
{
title : "q appearance theme",
appearances :
{
"fv/visual-pane" :
{
style : function(states)
{
return {
decorator : "visual-pane"
};
}
}
});
Decorator.js
-----------------
qx.Theme.define("q.theme.Decoration",
{
decorations :
{
"visual-pane" :
{
decorator: qx.ui.decoration.Single,
style :
{
widthTop : 1,
colorTop : "border-main",
style : "solid"
}
}
}
});
and in the class of the widget:
_createChildControlImpl : function(id)
{
var control;
switch(id)
{
....
case "visual-pane":
control = new qx.ui.core.scroll.ScrollPane();
break;
....
}
and I get the following error:
Error
in property decorator of class qx.ui.core.scroll.ScrollPane in method
setThemedDecorator with incoming value 'visual-pane-border': Is invalid!
throw new Error(msg + (this.__errors[id] || "Unknown reason: " + id));
What am I doing wrong here? Doesn't it work with a ScrollPane? Do I need to
enclose it with a Composite class? What is the problem?
Stefan
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