If it's JSON, I think the widget already converts it to a JSON object so
you shouldn't need the json_loads line, just your return value.

You could therefore use a lambda function here too:
lambda x: x["asn_org']



On Mon, 23 Nov 2020, 10:39 odea, <[email protected]> wrote:

> Works like a charm ! thanks :)
>
> and if it's a json (like http://ifconfig.co/json) ?
>
> I tried to create this simple json parser function, but I think I'm
> missing something :
>
> def parse_json(body)
>     x = json_loads(body)
>     return (x["asn_org"])
>
> ...
>
> widget.GenPollUrl(url="http://ifconfig.co/json",parse=parse_json)
>
> not a lot of documentation online :\
> Le dimanche 22 novembre 2020 à 22:31:47 UTC+1, elParaguayo a écrit :
>
>> Marc,
>>
>> Looking at the source, yes, you do need a parser but, here, it can be
>> really basic as you just want all the text from the web address.
>>
>> Try this:
>>
>> widget.GenPollUrl(url="http://ifconfig.co/country-iso";, json=False,
>> parse=lambda x: x.strip())
>>
>> The parser function just runs the strip function on the text you get back
>> which removes the trailing new line. Also, the widget defaults to expecting
>> json so you need to turn that off too.
>>
>> On Sunday, 22 November 2020 at 21:10:18 UTC odea wrote:
>>
>>>
>>> Hi,
>>> I'm a bit confused with the widget.GenPollUrl() function, do I really
>>> have to create a parser myself ? The URL I'm querying is this one :
>>> http://ifconfig.co/country-iso and I just have one word as a result.
>>> If I have to create a parser, if someone could give me the code for a
>>> very simple one that would be great !
>>> Thanks for your help,
>>> Rgds
>>> Marc
>>>
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