On 4/27/2007 12:55 PM, Duncan Murdoch wrote: > On 4/27/2007 11:34 AM, Gabor Grothendieck wrote: >> I noticed the following difference in parse(text = ...) between R >> 2.4.1 and R 2.5.0. >> >> === >> >>> parse(text = "\"^\" (x ,2 )") >> expression(x^2) >>> R.version.string >> [1] "R version 2.4.1 Patched (2006-12-30 r40331)" >> >> >> ==== >> >>> parse(text = "\"^\" (x ,2 )") >> expression("^" (x ,2 )) >>> R.version.string >> [1] "R version 2.5.0 RC (2007-04-16 r41194)" >> >> ==== >> >> Ryacas was depending on the behavior in R 2.4.1 so the new >> behavior breaks it. >> >> Is this intentional? a bug? How do I get the R 2.4.1 output >> from R 2.5.0 ? > > There's no difference in the parsing,
This isn't quite true, of course: in 2.5.0 the default parse output includes an attribute that references the original source. I think the rest of what I wrote is right: the difference is in the printing. > By default 2.5.0 will echo what you typed, whereas 2.4.1 will deparse. > You can get the 2.4.1 behaviour using options(keep.source=F) or > parse(text = "\"^\" (x ,2 )", srcfile=NULL) (as ?parse says). > > Duncan Murdoch > > ______________________________________________ > R-devel@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-devel ______________________________________________ R-devel@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-devel