Hi

On 1/02/2011 9:22 p.m., Martin Maechler wrote:
Henrik Bengtsson<h...@biostat.ucsf.edu>
     on Mon, 31 Jan 2011 11:16:59 -0800 writes:

     >  Hi, str() on raster objects fails for certain dimensions.  For
     >  example:

     >>  str(as.raster(0, nrow=1, ncol=100)) 'raster' chr [1, 1:100]
     >  "#000000" "#000000" "#000000" "#000000" ...

     >>  str(as.raster(0, nrow=1, ncol=101)) Error in `[.raster`(object,
     >  seq_len(max.len)) : subscript out of bounds

     >  This seems to do with how str() and "[.raster"() is coded; when
     >  subsetting as a vector, which str() relies on, "[.raster"()
     >  still returns a matrix-like object, e.g.

     >>  img<- as.raster(1:25, max=25, nrow=5, ncol=5);
     >>  img[1:2]
     >  [,1]      [,2]      [,3]      [,4]      [,5]
     >  [1,] "#0A0A0A" "#3D3D3D" "#707070" "#A3A3A3" "#D6D6D6"
     >  [2,] "#141414" "#474747" "#7A7A7A" "#ADADAD" "#E0E0E0"

     >  compare with:

     >>  as.matrix(img)[1:2]
     >  [1] "#0A0A0A" "#3D3D3D"


     >  The easy but incomplete fix is to do:

     >  str.raster<- function(object, ...) {
     >  str(as.matrix(object), ...);
     >  }

     >  Other suggestions?

The informal "raster" class is behaving ``illogical''
in the following sense:

  >  r<- as.raster(0, nrow=1, ncol=11)
  >  r[seq_along(r)]
  Error in `[.raster`(r, seq_along(r)) : subscript out of bounds

or, here equivalently,
  >  r[1:length(r)]
  Error in `[.raster`(r, 1:length(r)) : subscript out of bounds

When classes do behave in such a way, they definitely need their
own str() method.

However, the bug really is in "[.raster":
Currently,  r[i] is equivalent to  r[i,]  which is not at all
matrix-like and its help clearly says that subsetting should
work as for matrices.
A recent thread on R-help/R-devel has mentioned the fact that
"[" methods for matrix-like methods need to use both nargs() and
missing() and that "[.dataframe" has been the example to follow
"forever", IIRC already in S and S-plus as of 20 years ago.

The main motivation for non-standard behaviour here is to make sure that a subset of a raster object NEVER produces a vector (because the conversion back to a raster object then produces a single-column raster and that may be a "surprise"). Thanks for making the code more standard and robust.

The r[i] case is still tricky. The following behaviour is quite convenient ...

r[r == "black"] <- "white"

... but the next behaviour is quite jarring (at least in terms of the raster image that results from it) ...

r2 <- r[1:(nrow(r) + 1)]

So I think there is some justification for further non-standardness to try to ensure that the subset of a raster image always produces a sensible image. A simple solution would be just to outlaw r[i] for raster objects and force the user to write r[i, ] or r[, j], depending on what they want.

Paul

Thank you, Henrik, for the bug report.
Martin

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Dr Paul Murrell
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The University of Auckland
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