On Apr 23, 2013, at 21:51 , Patrick Burns wrote:
> Okay, that's a good reason why it shouldn't.
>
> Why it should is that I want to substitute
> the first element of a call to be a function
> including the namespace.
Offhand, I'd say that it shouldn't be a problem, but do you have a more
concrete example?
-pd
>
> Pat
>
>
> On 23/04/2013 18:32, peter dalgaard wrote:
>>
>> On Apr 23, 2013, at 19:23 , Patrick Burns wrote:
>>
>>> 'as.name' doesn't recognize a name with
>>> its namespace extension as a name:
>>>
>>>> as.name("lm")
>>> lm
>>>> as.name("stats::lm")
>>> `stats::lm`
>>>> as.name("stats:::lm")
>>> `stats:::lm`
>>>
>>>
>>> Is there a reason why it shouldn't?
>>
>> Any reason why it should? :: and ::: are operators. foo$bar is not the same
>> as `foo$bar` either.
>>
>
> --
> Patrick Burns
> pbu...@pburns.seanet.com
> twitter: @burnsstat @portfolioprobe
> http://www.portfolioprobe.com/blog
> http://www.burns-stat.com
> (home of:
> 'Impatient R'
> 'The R Inferno'
> 'Tao Te Programming')
--
Peter Dalgaard, Professor,
Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Email: pd....@cbs.dk Priv: pda...@gmail.com
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