Dear Duncan, On Fri, Mar 1, 2024 at 11:30 AM Duncan Murdoch <murdoch.dun...@gmail.com> wrote:
> ... > If you parse it with srcrefs, you could look at the source. The parser > doesn't record whether it was A -> B or B <- A anywhere else. > Thank you, this gets me closer but it still needs a little push: > foo <- function(x) { x <- substitute(x) return(attr(x, "srcref")[[2]]) } > foo(A -> B) NULL This seems to work, however: > foo({A -> B}) A -> B Is there a way to treat the formula as if it was enclosed between the curly brackets? Dmitri [[alternative HTML version deleted]] ______________________________________________ R-devel@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-devel