Le 11/12/2025 à 09:21, Peter Langfelder a écrit :
I think it's a bit of a quirk of rep:
rep("x")
[1] "x"
Help of 'rep' does state this:
The default behaviour is as if the call was
rep(x, times = 1, length.out = NA, each = 1)
So it seems to even be documented.
Right. But I think the initial question was rather "why f() does not
complain about missing n?"
It is because 'n' is not used in f() itself, it's just passed through in
his quality of "missing".
If you define f() where 'n' is used in some way, e.g. as follows:
f=function(n) rep("x", times=n+0L)
then it complains:
f()
Error in f() (from #1) : argument "n" is missing, with no default
Serguei.
Peter
Peter
On Thu, Dec 11, 2025 at 2:40 PM Henrik Bengtsson
<[email protected]> wrote:
What's going on here:
$ R --vanilla --quiet
f <- function(n) rep("x", times = n)
f()
[1] "x"
?
getRversion()
[1] ‘4.5.2’
/Henrik
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Cellule Mathématiques
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