On Tue, Oct 16, 2007 at 04:44:54PM -0400, Zembower, Kevin wrote: > Daniel, thanks for your suggestion. So, it's just done like this: > > pnorm(21, mean=20, sd=10/4) - pnorm(19, mean=20, sd=10/4) > [1] 0.3108435 > > # OR > > pnorm(21, mean=20, sd=10/sqrt(16)) - pnorm(19, mean=20, > sd=10/sqrt(16)) > [1] 0.3108435
You have calculated the probability that your sample estimate of the mean will be between 19 and 21, in your previous post you asked for 10 to 21, but I am guessing it was simply a typo. In any case, it looks like you are on the right track. -- Daniel Lakeland [EMAIL PROTECTED] http://www.street-artists.org/~dlakelan ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
