Henrique Dallazuanna wrote: >If I understand your question: > >df <- data.frame(x=rnorm(20), y=rnorm(20), z=rnorm(20)) >df <- as.matrix(df) >dim(df) >dim(df) <- c(10,6) >dim(df) <- c(5,12) > >On 29/10/2007, Weiwei Shi <[EMAIL PROTECTED]> wrote: > > >>hi, >> >>if I have 20 x 3 data.frame, how to split it into >>10 x 6 (moving the lower part of 10x3 to column) >> >>or >> >>5 x 12 >> >>thanks >> >> >> Hi,
I am not sure that the produced result is what is looked for; however the question is not clear to me either. The indicated code gives: df=data.frame(x=1:4,y=5:8) df=as.matrix(df) df newdf=df dim(newdf) = c(2,4) newdf while I would have thought that : newdf=cbind(df[1:2,], df[3:4,]) newdf was what was looked for. But there may be a quicker way. Regards, Thibaut. -- ###################################### Thibaut JOMBART CNRS UMR 5558 - Laboratoire de Biométrie et Biologie Evolutive Universite Lyon 1 43 bd du 11 novembre 1918 69622 Villeurbanne Cedex Tél. : 04.72.43.29.35 Fax : 04.72.43.13.88 [EMAIL PROTECTED] http://lbbe.univ-lyon1.fr/-Jombart-Thibaut-.html?lang=en http://pbil.univ-lyon1.fr/software/adegenet/ ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.