That solved it! Thank you very much!
On Mon, 5 Nov 2007, Prof Brian Ripley wrote: > On Mon, 5 Nov 2007, Christian Hennig wrote: > >> Dear list, >> >> order(x,y,z) returns a permutation to order x, ties broken by y, remaining >> ties broken by z. (And so on.) >> >> What I'd like to do is >> order(X), where X is a matrix (or a list or data frame if necessary) of >> unspecified size, which orders X[,1], ties broken by X[,2], remaining ties >> broken by X[,3] and so on - without having to know and to write down how >> many columns X has. >> >> Any ideas how to achieve that? > > For a list or data frame, do.call("order", X). > For a matrix, do.call("order", split(A, col(A))). > > -- > Brian D. Ripley, [EMAIL PROTECTED] > Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ > University of Oxford, Tel: +44 1865 272861 (self) > 1 South Parks Road, +44 1865 272866 (PA) > Oxford OX1 3TG, UK Fax: +44 1865 272595 > *** --- *** Christian Hennig University College London, Department of Statistical Science Gower St., London WC1E 6BT, phone +44 207 679 1698 [EMAIL PROTECTED], www.homepages.ucl.ac.uk/~ucakche ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.