Michael Lachmann wrote:
On 08/01/2010 08:48 PM, thmsfuller...@gmail.com wrote:
Hi,
The following two 'df's should be the same, although their
constructions are different.
But they aren't the same.
df1 <- data.frame(X=c(1, 2, 3), Y=c(4, 5, 6))
df2 <- data.frame(X=1:3, Y=4:6)
identical(df1, df2)
yields FALSE
Hmmm. quite strange.
*not* strange, in my opinion.
str(1:3)
int [1:3] 1 2 3
str( seq(1,3,by=1))
num [1:3] 1 2 3
str( seq.int(1,3,by=1))
num [1:3] 1 2 3
I don't quite understand why this latest is num, and not int.
Just read ?seq
Currently, ‘seq.int’ and the default method of ‘seq’ return a
result of type ‘"integer"’ (if it is representable as that and) if
‘from’ is (numerically equal to an) integer and, e.g., only ‘to’
is specified, or also if only ‘length’ or only ‘along.with’ is
specified. *Note:* this may change in the future and programmers
should not rely on it.
You're specifying 'by' in your calls.
Try
str(seq.int(1, 3))
str(seq(1, 3))
str( seq_along( seq(1,3,by=1)) )
int [1:3] 1 2 3
Finally, a way to generate the same as 1:3! The help states: "seq_along and
seq_length always return an integer vector."
str( seq.int( 1L, 3L, by=1L ) )
int [1:3] 1 2 3
You have to have all three, from to and by, as integers if you want an
integer vector, I think.
No. See above.
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