# just to clean it up for my own understanding, the "difference" approach as
you had suggested would be
x <- seq(.2, .3, by = .00001)
f1 <- function(x){
x*cos(x)-2*x**2+3*x-1
}
plot(x,f1(x), type = "l")
abline(h = -.1)
abline(v = x[which.min(abs(diff((f1(x) - (-.1))**2)))], lty = 'dotted')
points(x = x[which.min(abs(diff((f1(x) - (-.1))**2)))], y = -.1)
# and the uniroot approach is:
x <- seq(.2, .3, by = .01)
f1 <- function(x){
x*cos(x)-2*x**2+3*x-1
}
f2 <- function(x){
-.1
}
f3 <- function(x){
f1(x) - f2(x)
}
plot(x,f1(x), type = "l")
abline(h = -.1)
abline(v = uniroot(f = f3, interval = c(.2, .3))$root, lty = 'dotted')
points(x = uniroot(f = f3, interval = c(.2, .3))$root, y = -.1)
# Thanks David!
On Aug 12, 2010, at 1:33 PM, David Winsemius wrote:
On Aug 12, 2010, at 4:15 PM, TGS wrote:
> David, I was expecting this to work but how would I specify the vector in
> "diff()" in order for the following to work?
>
> x <- seq(.2, .3, by = .01)
> f <- function(x){
> x*cos(x)-2*x**2+3*x-1
> }
> plot(x,f(x), type = "l")
> abline(h = -.1)
> abline(v = x[which.min(abs(diff(c(-.1, f(x)))))], lty = 'dotted')
f2 <- function(x) -0.1
f3 <- function(x) f(x) -f2(x)
abline(v=uniroot(f3, c(0.2, 0.3) )$root)
points(x=uniroot(f3, c(0.2, 0.3) )$root, y= -0.1)
If you are going to use the differences, then you probably want to minimize
either the abs() or the square of the differences.
--
David.
>
> On Aug 12, 2010, at 1:00 PM, David Winsemius wrote:
>
>
> On Aug 12, 2010, at 3:54 PM, TGS wrote:
>
>> Actually I spoke too soon David.
>>
>> I'm looking for a function that will either tell me which point is the
>> intersection so that I'd be able to plot a point there.
>>
>> Or, if I have to solve for the roots in the ways which were demonstrated
>> yesterday, then would I be able to specify what the horizontal line is, for
>> instance in the case where y (is-not) 0?
>
> Isn't the abline h=0 represented mathematically by the equation y=0 and
> therefore you are solving just for the zeros of "f" (whaich are the same as
> for (f-0)? If it were something more interesting, like solving the
> intersection of two polynomials, you would be solving for the zeros of the
> difference of the equations. Or maybe I have not understood what you were
> requesting?
>
>
>>
>> On Aug 12, 2010, at 12:47 PM, David Winsemius wrote:
>>
>>
>> On Aug 12, 2010, at 3:43 PM, TGS wrote:
>>
>>> I'd like to plot a point at the intersection of these two curves. Thanks
>>>
>>> x <- seq(.2, .3, by = .01)
>>> f <- function(x){
>>> x*cos(x)-2*x**2+3*x-1
>>> }
>>>
>>> plot(x,f(x), type = "l")
>>> abline(h = 0)
>>
>> Would this just be the uniroot strategy applied to "f"? You then plot the x
>> and y values with points()
>>
>
>>
>
> David Winsemius, MD
> West Hartford, CT
>
>
David Winsemius, MD
West Hartford, CT
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