better try it this way: DF <- data.frame(y = rnorm(100), x = rchisq(100, df = 3)) m <- lm(y ~ x, DF) predict(m, data.frame(x = seq(-13, 13, 0.5)))
I hope it helps. Best, Dimitris On 8/16/2010 2:37 PM, Trafim Vanishek wrote:
Dear all, I have an error in the simple prediction function for lm(). Maybe someone experienced the same? xma<- matrix(data = 0, nrow = 100, ncol = 2) xma[, 1]<- rnorm(100) xma[, 2]<- rchisq(100, df = 3) m1<- lm(xma[, 1] ~ xma[, 2]) predict(m1, as.data.frame(seq(-13, 13, 0.5))) Thanks a lot, Trafim [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
-- Dimitris Rizopoulos Assistant Professor Department of Biostatistics Erasmus University Medical Center Address: PO Box 2040, 3000 CA Rotterdam, the Netherlands Tel: +31/(0)10/7043478 Fax: +31/(0)10/7043014 ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.