On Sep 1, 2010, at 4:17 PM, Jens Oldeland wrote:

Hi,

I am facing a problem with the legend, I donĀ“t know how to use the fill
option in the legend in order to achieve the same standard gray levels
that are plotted.

Sorry for this easy one, but I really did not find anything so far.

It works fine with color:

###### C O L O R
mat <- matrix(2,3,rep(2,6))
rownames(mat)<-c("A","B","C")
par(xpd=T, mar=par()$mar+c(2,0,0,0))
barplot(mat,col=rainbow(3))
legend(1,-2,legend=rownames(mat),fill=rainbow(3))

however

### G R A Y  ??

par(xpd=T, mar=par()$mar+c(2,0,0,0))
barplot(mat)  # now without color
legend(1,-2,legend=rownames(mat),fill=gray(0.1:0.3)) # this gray does
not work

It might be the grey/gray "not working", or it could be your assumption that 0.1:0.3 means what you you think.

> 0.1:0.3
[1] 0.1

I think it's safer to have the col= argument "lined up" with the fill argument. This "works" for me:

barplot(mat, col=gray(seq(0.1, 0.3, by=0.1)))  # now without color
legend(1,0,legend=rownames(mat),fill=gray(seq(0.1, 0.3, by=0.1))  )

This is a "counter-example" of what can go wrong otherwise:

barplot(mat, )  # now without color
 legend(1,0,legend=rownames(mat),fill=gray(1:3/3)) )

--

David Winsemius, MD
West Hartford, CT

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to