You've tried: gregexpr("b+", "abcdaabbc")
On Mon, Sep 27, 2010 at 12:48 PM, Titus von der Malsburg <malsb...@gmail.com > wrote: > Dear list! > > > gregexpr("a+(b+)", "abcdaabbc") > [[1]] > [1] 1 5 > attr(,"match.length") > [1] 2 4 > > What I want is the offsets of the matches for the group (b+), i.e. 2 > and 7, not the offsets of the complete matches. Is there a way in R > to get that? > > I know about gsubgn and strapply, but they only give me the strings > matched by groups not their offsets. > > I could write something myself that first takes the above matches > ("ab" and "aabb") and then searches again using only the group (b+). > For this to work, I'd have to parse the regular expression and search > several times (> 2, for nested groups) instead of just once. But I'm > sure there is a better way to do this. > > Thanks for any suggestion! > > Titus > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40" S 49° 16' 22" O [[alternative HTML version deleted]]
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.