Try this: x <- c(2,5,9,4,5,6,7,8) u <- replicate(20, sample(x, replace = TRUE)) t(u)
The first argument of replicate() is the number of times to iterate the process. I believe you'll find that it does indeed do random sampling; each row represents a nonparametric bootstrap sample of x. There are other ways of doing this; one is v <- matrix(sample(x, 160, replace = TRUE), ncol = 8, byrow = TRUE) HTH, Dennis On Tue, Sep 28, 2010 at 2:03 PM, Michael Larkin <mlar...@rsmas.miami.edu>wrote: > I am trying to get R to pick random integers from my dataset (i.e. > bootstrapping) with replacement. However, my attempts at this have been > unsuccessful. Here is a basic example of what I am doing: > > I have a data vector of 8 integers (data= 2,5,9,4,5,6,7,8). I used the > sample function and it worked but it only repeated my values in the exact > same order. It did not randomly sample them. Here is my code: > > sample(data, replace=TRUE) > > Any advice would be greatly appreciated. > > Mike > > > > > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
