a cleaner code would be:
sapply(2:20, function(i) c(mean=mean(x[1:i]), sd=sd(x[1:i])))
b
On Jan 30, 2008, at 3:16 PM, Henrique Dallazuanna wrote:
Try this:
x <- rnorm(20)
sapply(c("sd", "mean"), function(fun)lapply(lapply(lapply(2:20, seq,
from=1), function(.x)x[.x]), fun))
On 30/01/2008, cvandy <[EMAIL PROTECTED]> wrote:
I have a list of 20 values. The first time through a loop I want
to find the
mean and stnd.dev. of the first two values; the second time through
the loop
I want to find the mean and stnd. dev. of the first 3 values, etc.
until
the last time through the loop I want to find the mean and stnd.
dev. of all
20 values, so I end up with 19 means and stnd. deviations.
How would I construct such a loop?
Thanks.
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Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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and provide commented, minimal, self-contained, reproducible code.
______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
