Re: [R] Setting the names of a data.frame

[Ivan Calandra]

Hi,

The problem is that all your columns of sHeaders are factors. It might 
be better to set stringsAsFactors to FALSE when you build it.

Or you can do it with a for loop like this:
for (i in 1:length(sHeaders)){
 names(tData)[i] <- as.character(sHeaders[1,i])
}

Or with lapply:
names(tData) <- unlist(lapply(sHeaders[1, ], FUN=as.character))

HTH,
Ivan

Le 11/2/2010 14:58, Santosh Srinivas a écrit :
I have tData as below. I need to set the names with the headers from the
first row in sHeaders
Sorry .. forgot how to set the names from row in another data frame .. pls
advise.

names(tData) = sHeaders[1,] does not work correctly

Also, why doesn't drop.levels(sHeaders) not work?

dput(tData)
structure(list(V1 = structure(c(3L, 1L, 1L, 2L), .Label = c("P H Ravi
Kumar",
"Rahul Kumar Singh", "Ramu GSV"), class = "factor"), V2 = structure(c(1L,
3L, 3L, 2L), .Label = c("05/10/2010", "09/09/2010", "30/09/2010"
), class = "factor"), V3 = structure(c(2L, 1L, 1L, 2L), .Label = c("B",
"S"), class = "factor"), V4 = structure(c(2L, 3L, 3L, 1L), .Label =
c("2120",
"4000", "11000"), class = "factor"), V5 = structure(c(1L, 2L,
2L, 1L), .Label = c("", "0.01"), class = "factor"), V6 = structure(c(2L,
3L, 3L, 1L), .Label = c("765", "1000", "11000"), class = "factor"),
     V7 = structure(c(1L, 2L, 2L, 1L), .Label = c("", "0.01"), class =
"factor")), .Names = c("V1",
"V2", "V3", "V4", "V5", "V6", "V7"), row.names = 5:8, class = "data.frame")


dput(sHeaders)
structure(list(V1 = structure(1L, .Label = c("Name of Acquirer / Seller",
"Qty", "Ramu GSV"), class = "factor"), V2 = structure(3L, .Label =
c("05/10/2010",
"%", "Transaction Date"), class = "factor"), V3 = structure(1L, .Label =
c("Buy /Sale",
"Qty", "S"), class = "factor"), V4 = structure(3L, .Label = c("4000",
"%", "No.of Shares Transacted"), class = "factor"), V5 = structure(2L,
.Label = c("",
"Holding after Transaction"), class = "factor"), V6 = structure(NA_integer_,
.Label = "1000", class = "factor"),
     V7 = structure(NA_integer_, .Label = "", class = "factor")), .Names =
c("V1",
"V2", "V3", "V4", "V5", "V6", "V7"), row.names = 3L, class = "data.frame")


Thanks very  much.

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


--
Ivan CALANDRA
PhD Student
University of Hamburg
Biozentrum Grindel und Zoologisches Museum
Abt. Säugetiere
Martin-Luther-King-Platz 3
D-20146 Hamburg, GERMANY
+49(0)40 42838 6231
ivan.calan...@uni-hamburg.de

**********
http://www.for771.uni-bonn.de
http://webapp5.rrz.uni-hamburg.de/mammals/eng/mitarbeiter.php

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.