Mirko,
Here is a solution - I am sure other R mentors would find a more efficient
one
> x <- data.frame(A=c(1, 2, 2), B=c(4, 5, 5))
> x <- rbind(x,x)
> r <- c(2,5)
>
> (rowfind=apply(x,1,FUN=function(row,add){isTRUE(all.equal(row,add,check.attributes
= FALSE))},add=r))
1 2 3 4 5 6
FALSE TRUE TRUE FALSE TRUE TRUE
> (rowfindindex=(1:nrow(x))[rowfind])
[1] 2 3 5 6
Hope this help,
Eric
2010/11/25 Luedde, Mirko <mirko.lue...@sap.com>
> Dear all,
>
> this looks pretty much a standard problem, but I couldn't find a
> satisfying and understandable solution.
>
> (A) Given a data frame (or matrix), e.g.
>
> x <- data.frame(A=c(1, 2, 2), B=c(4, 5, 5))
>
> and a row of this data frame, e.g.
>
> r <- c(2, 5)
>
> I need to find one row index i (or all such indices) such that r
> is at the i-th row in x, that is, the expression
>
> all(x[i,]==as.list(r))
>
> evaluates to TRUE. I can not evaluate an expression like
>
> x[x[,1]==2 & x[,2]==5,]
>
> because I do not know in advance how many columns x will have.
>
> Basically, thus, I'm looking for an equivalent of "vectorfind" in
> Scilab.
>
> (B) Which would be the most appropriate data type for x, matrix or
> data frame or another type?
>
> (C) What will be better, searching for rows or searching for columns?
>
> Thank you for your help!
>
> Best, Mirko
>
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> and provide commented, minimal, self-contained, reproducible code.
>
--
Eric Lecoutre
Consultant - Business & Decision
Business Intelligence & Customer Intelligence
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