Hi Marianne,
Please consider the following:
with(table, aggregate(rt, list(group, session), FUN = median))
HTH,
Jorge
On Wed, Dec 8, 2010 at 9:29 AM, Marianne Stephan <> wrote:
>
> Hello everybody,
> I would like to calculate the median for each factor combination, with only
> one value per factor combination as an output.
> Could anybody help me?
>
>
> For example:
> # make table
> g<-1:2
> group<-rep(g, each=5)
> session<-c(1,1,2,2,2,1,1,1,2,2)
> rt<-seq(length=10,300, 800)
> rt<-round(rt, digits=2)
> table<-data.frame(group, session, rt)
> table
>
> group session rt
> 1 1 1 300.00
> 2 1 1 355.56
> 3 1 2 411.11
> 4 1 2 466.67
> 5 1 2 522.22
> 6 2 1 577.78
> 7 2 1 633.33
> 8 2 1 688.89
> 9 2 2 744.44
> 10 2 2 800.00
>
>
>
>
> Besides others I tried the following:
> median<-ave(rt, group, session, FUN=median)
> median<-frameApply(table,by=c("group", "session"), on="rt", fun=median)
>
> I would appreciate your help a lot.
> Marianne
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>
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