Dear Sir, Sorry to bother you again. Sir, the R code provided by you gives me following output.
> yy <- lapply(c(257, 520, 110), seq, to=0, by=-100) > yy [[1]] [1] 257 157 57 [[2]] [1] 520 420 320 220 120 20 [[3]] [1] 110 10 The biggest constraint for me is here as an example I have taken only three cases i.e. c(257, 520, 110), however in reality I will be dealing with no of cases and that number is unknown. But your code will certainly generate me the required numbers. In above case for doing further calculations, I can define say yy1 = as.numeric(yy[[1]]) yy2 = as.numeric(yy[2]]) yy3 = as.numeric(yy[[3]]) But when the number of cases are unknown, perhaps this is not the practical way of me defining individually. So is there any way that I can have all the sequence numbers generated can be accommodated in a single dataframe. I sincerely apologize for disturbing you Sir and hope I am able to put up my problem in a proper manner. Regards Vincy Pyne --- On Thu, 12/9/10, Jan van der Laan <rh...@eoos.dds.nl> wrote: From: Jan van der Laan <rh...@eoos.dds.nl> Subject: Re: [R] Sequence generation in a table To: r-help@r-project.org, vincy_p...@yahoo.ca Received: Thursday, December 9, 2010, 10:57 AM Vincy, I suppose the following does what you want. yy is now a list which allows for differing lengths of the vectors. > yy <- lapply(c(257, 520, 110), seq, to=0, by=-100) > yy[[1]] [1] 257 157 57 > yy[[2]] [1] 520 420 320 220 120 20 Regards, Jan On 9-12-2010 11:40, Vincy Pyne wrote: > c(257, 520, 110) [[alternative HTML version deleted]]
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