On Sun, 12 Dec 2010, jagdeesh_mn wrote:
Hi,
Suppose i have generated an object using the following :
fit <- rpart(Kyphosis ~ Age + Number + Start, data=kyphosis)
And when i print fit, i get the following :
n= 81
node), split, n, loss, yval, (yprob)
* denotes terminal node
1) root 81 17 absent (0.7901235 0.2098765)
2) Start>=8.5 62 6 absent (0.9032258 0.0967742)
4) Start>=14.5 29 0 absent (1.0000000 0.0000000) *
5) Start< 14.5 33 6 absent (0.8181818 0.1818182)
10) Age< 55 12 0 absent (1.0000000 0.0000000) *
11) Age>=55 21 6 absent (0.7142857 0.2857143)
22) Age>=111 14 2 absent (0.8571429 0.1428571) *
23) Age< 111 7 3 present (0.4285714 0.5714286) *
3) Start< 8.5 19 8 present (0.4210526 0.5789474) *
Is it possible to extract the splits alone as a matrix using rpart.object?
If so, how?
What do you think 'rpart.object' is? There is no such function in R.
If you read help("rpart.object") it describes the returned object.
You are probably looking for fit$frame, but if you want something
else, study
rpart:::print.rpart
to see how that output is computed.
Regards,
Jagdeesh
--
Brian D. Ripley, rip...@stats.ox.ac.uk
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
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